1864 United States presidential election in Vermont

Main article: 1864 United States presidential election

1864 United States presidential election in Vermont

←  1860 November 8, 1864 1868  →

Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois New Jersey Running mate Andrew Johnson George H. Pendleton Electoral vote 5 0 Popular vote 42,420 13,322 Percentage 76.10% 23.90%

County results Municipality results Lincoln   50–60%   60–70%   70–80%   80–90%   90–100% McClellan   50–60%   60–70%   80–90%   90–100%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln National Union

The 1864 United States presidential election in Vermont took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the National Union candidate, incumbent Republican President Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate, George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a wide margin of 52.20%.

With 76.10% of the popular vote, Lincoln's victory with in the state would be his second strongest victory in the country in terms of percentage in the popular vote after Kansas. ^[1]

Results

1864 United States presidential election in Vermont [2]
Party		Candidate	Votes	Percentage	Electoral votes
	National Union	Abraham Lincoln (incumbent)	42,420	76.10%	5
	Democratic	George B. McClellan	13,322	23.90%	0
Totals			55,742	100.0%	26

See also

• United States presidential elections in Vermont

References

1. "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
2. "1864 Presidential General Election Results - Vermont".