1910 Vermont gubernatorial election

For related races, see 1910 United States gubernatorial elections.

1910 Vermont gubernatorial election

←  1908 September 6, 1910 (1910-09-06) 1912  →

Nominee John A. Mead Charles D. Watson Party Republican Democratic Popular vote 35,263 17,425 Percentage 64.2% 31.7%

County results Mead:     40–50%     50–60%     60–70%     70–80%     80–90%

Governor before election George H. Prouty Republican Elected Governor John A. Mead Republican

The 1910 Vermont gubernatorial election took place on September 6, 1910. Incumbent Republican George H. Prouty, per the "Mountain Rule", ^[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson to succeed him.

Marshall J. Hapgood, who ran a quixotic campaign for the Republican gubernatorial nomination, filed Vermont's first-ever campaign finance report, which indicated that he spent $103.76 (equivalent to $3,393in 2023). ^[2]

Results

1910 Vermont gubernatorial election ^[3]

Party		Candidate	Votes	%	±%
	Republican	John A. Mead	35,263	64.2
	Democratic	Charles D. Watson	17,425	31.7
	Prohibition	Edwin R. Towle	1,044	1.9
	Socialist	Chester E. Ordway	1,055	1.9
	N/A	Other	141	0.3
Total votes			'54,928'	'100'

References

1. Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
2. "Politics and Power Forever Linked With Money". Rutland Herald . September 18, 1994. p. 47. Archived from the original on December 9, 2022 – via Newspapers.com.
3. "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.