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Elections in Vermont |
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The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.
With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote. [1]
1876 United States presidential election in Vermont [2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Rutherford B. Hayes of Ohio | William A. Wheeler of New York | 44,091 | 68.30% | 5 | 100.00% | ||
Democratic | Samuel J. Tilden of New York | Thomas A. Hendricks of Indiana | 20,254 | 31.38% | 0 | 0.00% | ||
N/A | Others | Others | 208 | 0.32% | 0 | 0.00% | ||
Total | 64,553 | 100.00% | 5 | 100.00% |
Presidential elections were held in the United States on November 7, 1876. Republican Governor Rutherford B. Hayes of Ohio defeated Democrat Governor Samuel J. Tilden of New York. Following President Ulysses S. Grant's decision to retire after his second term, U.S. Representative James G. Blaine emerged as frontrunner for the Republican nomination; however, Blaine was unable to win a majority at the 1876 Republican National Convention, which settled on Hayes as a compromise candidate. The 1876 Democratic National Convention nominated Tilden on the second ballot.
William Almon Wheeler was an American politician and attorney who served as the 19th vice president of the United States from 1877 to 1881 under President Rutherford B. Hayes. A member of the Republican Party, he previously served as a United States representative from New York from 1861 to 1863 and 1869 to 1877.
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