1876 United States presidential election in Nebraska

Main article: 1876 United States presidential election

1876 United States presidential election in Nebraska

←  1872 November 7, 1876 1880  →

Nominee Rutherford B. Hayes Samuel J. Tilden Party Republican Democratic Home state Ohio New York Running mate William A. Wheeler Thomas A. Hendricks Electoral vote 3 0 Popular vote 31,915 17,413 Percentage 64.70% 35.30%

County Results Hayes   40–50%   50–60%   60–70%   70–80%   80–90%   90–100% Tilden   40–50%   50–60%   60–70%   70–80%

President before election Ulysses S. Grant Republican Elected President Rutherford B. Hayes Republican

The 1876 United States presidential election in Nebraska took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Nebraska voted for the Republican nominee, Ohio Governor Rutherford B. Hayes, over the Democratic nominee, New York Governor Samuel J. Tilden by a margin of 29.4%.

With 64.70% of the popular vote, Nebraska would be Hayes' second strongest victory in terms of percentage in the popular vote after Vermont. ^[1]

Results

1876 United States presidential election in Nebraska [2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Rutherford B. Hayes of Ohio	William A. Wheeler of New York	31,915	64.70%	3	100.00%
	Democratic	Samuel J. Tilden of New York	Thomas A. Hendricks of Indiana	17,413	35.30%	0	0.00%
Total				49,328	100.00%	3	100.00%

See also

• United States presidential elections in Nebraska

References

1. "1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
2. "1876 Presidential General Election Results - Nebraska".