1868 United States presidential election in Nebraska

Main article: 1868 United States presidential election

1868 United States presidential election in Nebraska

November 3, 1868 1872  →

Nominee Ulysses S. Grant Horatio Seymour Party Republican Democratic Home state Illinois New York Running mate Schuyler Colfax Francis Preston Blair Jr. Electoral vote 3 0 Popular vote 9,772 5,519 Percentage 63.91% 36.09%

Grant   50–60%   60–70%   70–80%   80–90%   90–100% Seymour   50–60%   90–100%

President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

The 1868 United States presidential election in Nebraska took place on November 3, 1868, as part of the 1868 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president. ^[1]

Nebraska participated in its first ever presidential election, having become the 37th state on March 1, 1867. The state was won by Ulysses S. Grant, formerly the 6th Commanding General of the United States Army (R-Illinois), running with Speaker of the House Schuyler Colfax, with 63.91% of the popular vote, against the 18th governor of New York, Horatio Seymour (D–New York), running with former Senator Francis Preston Blair Jr., with 36.09% of the vote. ^[1]

Results

1868 United States presidential election in Nebraska [1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	9,772	63.91%	3	100.00%
	Democratic	Horatio Seymour of New York	Francis Preston Blair Jr. of Missouri	5,519	36.09%	0	0.00%
Total				15,291	100.00%	3	100.00%

See also

• United States presidential elections in Nebraska

References

1. "1868 Presidential Election Results Nebraska".