1868 United States presidential election in Missouri

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1868 United States presidential election in Missouri
Flag of Missouri.svg
  1864 November 3, 1868 1872  
  Ulysses S Grant by Brady c1870-restored (3x4 crop).jpg Hon. Horatio Seymour, N.Y - NARA - 528568 (cropped).jpg
Nominee Ulysses S. Grant Horatio Seymour
Party Republican Democratic
Home state Ohio New York
Running mate Schuyler Colfax Francis Preston Blair Jr.
Electoral vote110
Popular vote86,86065,628
Percentage56.96%43.04%

Missouri Presidential Election Results 1868.svg
County Results

President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Missouri took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 11 representatives, or electors, to the Electoral College, who voted for president and vice president. [1]

Contents

Missouri was won by Ulysses S. Grant, formerly the 6th Commanding General of the United States Army (R-Ohio), running with Speaker of the House Schuyler Colfax, with 56.96% of the popular vote, against the 18th governor of New York, Horatio Seymour (DNew York), running with former Senator Francis Preston Blair Jr., with 43.04% of the vote. [1]

Grant's victory in Missouri made him the first Republican presidential candidate to win the state, although President Abraham Lincoln had won the state on the National Union ticket in 1864. Grant would also be the only Republican to carry the state until Theodore Roosevelt won it in 1904.

Results

1868 United States presidential election in Missouri [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Republican Ulysses S. Grant of Ohio Schuyler Colfax of Indiana 86,86056.96%11100.00%
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 65,62843.04%00.00%
Total152,488100.00%11100.00%

See also

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References

  1. 1 2 3 "1868 Presidential Election Results Missouri".