1892 Missouri lieutenant gubernatorial election

1892 Missouri lieutenant gubernatorial election

←  1888 November 8, 1892 1896  →

Nominee John Baptiste O'Meara Rudolph W. Mueller George W. Williams Party Democratic Republican Populist Popular vote 263,000 231,184 41,293 Percentage 48.73% 42.84% 7.65%

County results O'Meara:     30–40%     40–50%     50–60%     60–70%     70–80%     80–90% Mueller:     40–50%     50–60%     60–70%     70–80% Tie:     40–50%

Lieutenant Governor before election Stephen Hugh Claycomb Democratic Elected Lieutenant Governor John Baptiste O'Meara Democratic

The 1892 Missouri lieutenant gubernatorial election was held on November 8, 1892, in order to elect the lieutenant governor of Missouri. Democratic nominee John Baptiste O'Meara defeated Republican nominee Rudolph W. Mueller, People's nominee George W. Williams and Prohibition nominee William S. Crouch. ^[1]

General election

On election day, November 8, 1892, Democratic nominee John Baptiste O'Meara won the election by a margin of 31,816 votes against his foremost opponent Republican nominee Rudolph W. Mueller, thereby retaining Democratic control over the office of lieutenant governor. O'Meara was sworn in as the 22nd lieutenant governor of Missouri on January 9, 1893. ^[2]

Results

Missouri lieutenant gubernatorial election, 1892

Party		Candidate	Votes	%
	Democratic	John Baptiste O'Meara	263,000	48.73
	Republican	Rudolph W. Mueller	231,184	42.84
	Populist	George W. Williams	41,293	7.65
	Prohibition	William S. Crouch	4,204	0.78
Total votes			539,681	100.00
	Democratic hold

See also

• 1892 Missouri gubernatorial election

References

1. "1892 Lt. Gubernatorial General Election Results - Missouri". uselectionatlas.org. July 8, 2016. Retrieved 2024-10-22.
2. "MO Lt. Governor". ourcampaigns.com. December 17, 2007. Retrieved 2024-10-22.