1832 United States presidential election in Missouri

Main article: 1832 United States presidential election

1832 United States presidential election in Missouri

←  1828 November 2 – December 5, 1832 1836  →

Nominee Andrew Jackson Henry Clay Party Democratic National Republican Home state Tennessee Kentucky Running mate Martin Van Buren John Sergeant Electoral vote 4 0 Popular vote 8,904 4,760 Percentage 65.16% 34.84%

County Results Jackson   40–50%   70–80%   80–90%   90–100% Clay   50–60%   60–70% No Data/Vote

The 1832 United States presidential election in Missouri took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Missouri voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Missouri by a margin of 30.33%. It is frequently reported that Jackson's popular vote win was unanimous, having received 5,159 or 5,192 votes. However, this was likely a reference to Jackson's plurality over Clay that was confounded with his total vote. ^[1]

Results

1832 United States presidential election in Missouri [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Andrew Jackson (incumbent)	8,904	65.16%	4
	National Republican	Henry Clay	4,760	34.84%	0
Totals			13,664	100.0%	4

See also

• United States presidential elections in Missouri

References

1. Dubin, Michael J. United States Presidential Elections. 1788–1870: The Official Results by County and State. ISBN   978-0-7864-6422-7.
2. "Missouri Politics". Jeffersonian Republican. September 21, 1833. p. 2.