1832 United States presidential election in Indiana

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1832 United States presidential election in Indiana
Flag of Indiana.svg
  1828 November 2 – December 5, 1832 1836  
  Andrew jackson head.jpg Henry Clay (copy after Edward Dalton Marchant).jpg
Nominee Andrew Jackson Henry Clay
Party Democratic National Republican
Home state Tennessee Kentucky
Running mate Martin Van Buren John Sergeant
Electoral vote90
Popular vote31,551/31,65215,472/25,473
Percentage67.10%/55.3832.90%/44.57

The 1832 United States presidential election in Indiana took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Indiana voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Indiana by a margin of 10.81%/34.20%.

As of 2020, this remains the strongest performance by a Democrat in Indiana. [1] (If 34.20% is correct than yes)

Results

1832 United States presidential election in Indiana [2]
PartyCandidateVotesPercentageElectoral votes
Democratic Andrew Jackson (incumbent)31,55167.10%9
National Republican Henry Clay 15,47232.90%0
Totals47,023100.0%9

See also

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References

  1. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved January 10, 2023.
  2. "1832 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved April 12, 2013.