1856 United States presidential election in Indiana

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1856 United States presidential election in Indiana
Flag of Indiana.svg
  1852 November 4, 1856 1860  
  James Buchanan (cropped).jpg John Charles Fremont crop.jpg Fillmore (cropped).jpg
Nominee James Buchanan John C. Frémont Millard Fillmore
Party Democratic Republican Know Nothing
Home state Pennsylvania California New York
Running mate John C. Breckinridge William L. Dayton Andrew J. Donelson
Electoral vote1300
Popular vote118,67094,37522,386
Percentage50.41%40.09%9.51%

Indiana Presidential Election Results 1856.svg
County Results

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Indiana took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Indiana voted for the Democratic candidate, James Buchanan, over Republican candidate John C. Frémont and American Party candidate Millard Fillmore. Buchanan won Indiana by a margin of 10.32 percentage points.

A Democratic presidential nominee would not win Indiana again until Samuel J. Tilden narrowly won it in 1876.

Results

1856 United States presidential election in Indiana [1] [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 118,67050.41%13100.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 94,37540.09%00.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 22,3869.51%00.00%
Total235,431100.00%13100.00%

See also

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References

  1. "1856 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved December 3, 2017.
  2. "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.