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Elections in Maine |
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The 1856 United States presidential election in Maine took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.
Maine voted for the Republican candidate, John C. Frémont, over the Democratic candidate, James Buchanan, and the Know Nothing candidate, Millard Fillmore. Frémont won the state by a margin of 25.66%.
With 61.34% of the popular vote, Maine would prove to be Frémont's third strongest state in the 1856 election after Vermont and Massachusetts. [1]
1856 United States presidential election in Maine [2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | John C. Frémont of California | William L. Dayton of New Jersey | 67,279 | 61.34% | 8 | 100.00% | ||
Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 39,140 | 35.68% | 0 | 0.00% | ||
Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 3,270 | 2.98% | 0 | 0.00% | ||
Total | 109,689 | 100.00% | 8 | 100.00% |
The 1856 United States presidential election was the 18th quadrennial presidential election, held on Tuesday, November 4, 1856. In a threeway election, Democrat James Buchanan defeated Republican nominee John C. Frémont and Know Nothing/Whig nominee Millard Fillmore. The main issue was the expansion of slavery as facilitated by the Kansas–Nebraska Act of 1854. Buchanan defeated President Franklin Pierce at the 1856 Democratic National Convention for the nomination. Pierce had become widely unpopular in the North because of his support for the pro-slavery faction in the ongoing civil war in territorial Kansas, and Buchanan, a former Secretary of State, had avoided the divisive debates over the Kansas–Nebraska Act by being in Europe as the Ambassador to the United Kingdom.
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