1824 United States presidential election in Maine

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1824 United States presidential election in Maine
Flag of the United States (1822-1836).svg
  1820 October 26 – December 2, 1824 1828  
  John Quincy Adams 1858 crop.jpg WilliamHCrawford.jpg
Nominee John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Massachusetts Georgia
Running mate John C. Calhoun Nathaniel Macon
Electoral vote90
Popular vote10,2892,336
Percentage81.50%18.50%

1824 Maine Presidential Election Results By County.svg
County Results
Adams
  50–60%
  70–80%
  80–90%
  90–100%

The 1824 United States presidential election in Maine took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the presidency. Maine voted for John Quincy Adams over William H. Crawford. Adams won Maine by a margin of 63.0%.

Results

1824 United States presidential election in Maine [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican John Quincy Adams 10,28981.50%9
Democratic-Republican William H. Crawford 2,33618.50%0
Totals12,625100.0%9

See also

Notes

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    References

    1. "1824 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved 27 February 2013.