1824 United States presidential election in New Hampshire

Main article: 1824 United States presidential election

1824 United States presidential election in New Hampshire

←  1820 October 26 – December 2, 1824 1828  →

Nominee John Quincy Adams William H. Crawford Party Democratic-Republican Democratic-Republican Home state Massachusetts Georgia Running mate John C. Calhoun Nathaniel Macon Electoral vote 8 0 Popular vote 9,389 643 Percentage 93.59% 6.41%

County results Adams   90–100%

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

The 1824 United States presidential election in New Hampshire took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the presidency. New Hampshire voted for John Quincy Adams over William H. Crawford, Andrew Jackson, and Henry Clay. Adams won New Hampshire by a margin of 87.18%.

Results

1824 United States presidential election in New Hampshire [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	John Quincy Adams	9,389	93.59%	8
	Democratic-Republican	William H. Crawford	643	6.41%	0
Totals			10,032	100.0%	8

See also

• United States presidential elections in New Hampshire

References

1. "1824 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved February 27, 2013.