1824 United States presidential election in New Hampshire

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1824 United States presidential election in New Hampshire
Flag of New Hampshire.svg
  1820 October 26 – December 2, 1824 1828  
  John Quincy Adams 1858 crop.jpg WilliamHCrawford.jpg
Nominee John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Massachusetts Georgia
Running mate John C. Calhoun Nathaniel Macon
Electoral vote80
Popular vote9,389643
Percentage93.59%6.41%

New Hampshire Presidential Election Results 1824.svg
County Results
Adams
  90-100%


President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in New Hampshire took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. New Hampshire voted for John Quincy Adams over William H. Crawford, Andrew Jackson, and Henry Clay. Adams won New Hampshire by a margin of 87.18%.

Results

1824 United States presidential election in New Hampshire [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican John Quincy Adams 9,38993.59%8
Democratic-Republican William H. Crawford 6436.41%0
Totals10,032100.0%8

See also

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References

  1. "1824 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved February 27, 2013.