1890 New Hampshire gubernatorial election

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1890 New Hampshire gubernatorial election
Flag of New Hampshire.svg
  1888 November 4, 1890 1892  
  Hiram A. Tuttle.jpg No image.svg
Nominee Hiram A. Tuttle Charles H. Amsden
Party Republican Democratic
Popular vote42,47942,386
Percentage49.26%49.15%

1890 New Hampshire gubernatorial election results map by county.svg
County results
Tuttle:     40–50%     50–60%
Amsden:     40–50%     50–60%

Governor before election

David H. Goodell
Republican

Elected Governor

Hiram A. Tuttle
Republican

The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.

Contents

General election

Candidates

Major party candidates

Other candidates

Results

1890 New Hampshire gubernatorial election [1]
PartyCandidateVotes%±%
Republican Hiram A. Tuttle 42,479 49.26%
Democratic Charles H. Amsden42,38649.15%
Prohibition Josiah M. Fletcher1,3431.56%
Majority93
Turnout
Republican hold Swing

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References

  1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved July 16, 2020.