1840 United States presidential election in New Hampshire

Main article: 1840 United States presidential election

1840 United States presidential election in New Hampshire

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Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate none John Tyler Electoral vote 7 0 Popular vote 32,774 26,310 Percentage 54.66% 43.88%

County Results Van Buren   50–60%   60–70%   70–80% Harrison   50–60%   60–70%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

A presidential election was held in New Hampshire on November 2, 1840 as part of the 1840 United States presidential election. ^[1] Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 10.78%.

Results

1840 United States presidential election in New Hampshire [2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	32,774	54.66%	7	100.00%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	26,310	43.88%	0	0.00%
	Liberty	James G. Birney of New York	Thomas Earle of Pennsylvania	872	1.45%	0	0.00%
Total				59,956	100.00%	7	100.00%

See also

• United States presidential elections in New Hampshire

References

1. Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
2. "1840 Presidential General Election Results – New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.