1840 United States presidential election in New Hampshire

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1840 United States presidential election in New Hampshire
Flag of New Hampshire.svg
  1836 October 30 – December 2, 1840 1844  
  Martin Van Buren circa 1837 crop.jpg William Henry Harrison crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running matenone John Tyler
Electoral vote70
Popular vote32,77426,310
Percentage54.66%43.88%

New Hampshire Presidential Election Results 1840.svg
County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in New Hampshire took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 10.78%.

Results

1840 United States presidential election in New Hampshire [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 32,77454.66%7100.00%
Whig William Henry Harrison of Ohio John Tyler of Virginia 26,31043.88%00.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 8721.45%00.00%
Total59,956100.00%7100.00%

See also

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References

  1. "1840 Presidential General Election Results – New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.