1840 United States presidential election in North Carolina

Main article: 1840 United States presidential election

1840 United States presidential election in North Carolina

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Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 15 0 Popular vote 46,567 34,168 Percentage 57.68% 42.32%

County Results Harrison   50–60%   60–70%   70–80%   80–90%   90–100% Van Buren   50–60%   60–70%   70–80%   80–90%   90–100% No Data/Vote

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

A presidential election was held in North Carolina on November 12, 1840 as part of the 1840 United States presidential election. ^[1] Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

North Carolina voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won North Carolina by a margin of 15.36%.

With 57.68% of the popular vote, North Carolina would prove to be Harrison's fifth strongest state after Kentucky, Vermont, Rhode Island and Louisiana. ^[2]

Results

United States presidential election in North Carolina, 1840 [3]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	46,567	57.68%	15	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	34,168	42.32%	0	0.00%
Total				80,735	100.00%	15	100.00%

References

1. Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
2. "1840 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
3. "1840 Presidential General Election Results - North Carolina". U.S. Election Atlas. Retrieved December 23, 2013.