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| Elections in Rhode Island |
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A presidential election was held in Rhode Island on November 2, 1840 as part of the 1840 United States presidential election. [1] Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
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Rhode Island voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Rhode Island by a margin of 22.93%.
With 61.22% of the popular vote, Rhode Island would be Harrison's third strongest state in the 1840 election after Kentucky and Vermont. [2]
