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| Elections in Rhode Island |
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The 1804 United States presidential election in Rhode Island took place as part of the 1804 United States presidential election. Voters chose four representatives, or electors, to the Electoral College who voted for president and vice president.
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Rhode Island voted for the Democratic-Republican candidate, Thomas Jefferson, over the Federalist candidate, Charles Cotesworth Pinckney. Jefferson won Rhode Island by a margin of 100.00%, the largest margin and landslide victory ever since in the state, because Pinckney was not on the ballot.
