1870 Rhode Island gubernatorial election

Last updated
1870 Rhode Island gubernatorial election
  1869 April 6, 18701871 
  SethPadelford.jpg
Nominee Seth Padelford Lyman Pierce
Party Republican Democratic
Popular vote10,3376,295
Percentage62.15%37.85%

Governor before election

Seth Padelford
Republican

Elected Governor

Seth Padelford
Republican

The 1870 Rhode Island gubernatorial election took place on April 6, 1870 in order to elect the governor of Rhode Island. [1] Republican candidate and incumbent governor Seth Padelford won his second one-year term as governor [2] over Democratic candidate Lyman Pierce. [3]

Contents

Candidates

Republican Party

Democratic Party

Election

Statewide

1870 Rhode Island gubernatorial election [1]
PartyCandidateVotes%
Republican Seth Padelford 10,33762.15
Democratic Lyman Pierce6,29537.85
Total votes16,632 100.00
Republican hold

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References

  1. 1 2 Dubin, Michael J. (2014). United States Gubernatorial Elections, 1861-1911 | The Official Results by State and County. McFarland. pp. 213–214. ISBN   9780786456468.
  2. 1 2 "Seth Padelford". National Governors Association. 1 January 2019. Retrieved 27 March 2024.
  3. "Our State Election". The Bristol Phoenix. 2 April 1870. Retrieved 27 March 2024 via NewspaperArchive.com.
  4. "Democratic Nominations". Newport Daily News . 25 March 1869. Retrieved 27 March 2024 via Newspapers.com.