1870 Rhode Island gubernatorial election

1870 Rhode Island gubernatorial election

←  1869 April 6, 1870 1871  →

Nominee Seth Padelford Lyman Pierce Party Republican Democratic Popular vote 10,337 6,295 Percentage 62.15% 37.85%

County results Padelford:      50–60%     60–70%

Governor before election Seth Padelford Republican Elected Governor Seth Padelford Republican

The 1870 Rhode Island gubernatorial election took place on April 6, 1870, in order to elect the governor of Rhode Island. ^[1] Republican candidate and incumbent governor Seth Padelford won his second one-year term as governor ^[2] over Democratic candidate Lyman Pierce. ^[3]

Candidates

Republican Party

• Seth Padelford, the Republican nominee, was the incumbent governor. He had previously served in the Rhode Island House of Representatives for two years, ran and lost in the 1860 Rhode Island gubernatorial election as the Republican nominee, and was the Lieutenant Governor of Rhode Island from 1863 to 1865 under James Y. Smith. ^[2]

Democratic Party

• Lyman Pierce, the Democratic nominee, had been nominated in the previous year's election to become the governor of Rhode Island. ^[4]

Election

Statewide

1870 Rhode Island gubernatorial election ^[1]

Party		Candidate	Votes	%
	Republican	Seth Padelford	10,337	62.15
	Democratic	Lyman Pierce	6,295	37.85
Total votes			16,632	100.00
	Republican hold

References

1. Dubin, Michael J. (2014). United States Gubernatorial Elections, 1861-1911 | The Official Results by State and County. McFarland. p. 5. ISBN   9780786456468.
2. "Seth Padelford". National Governors Association. January 1, 2019. Retrieved March 27, 2024.
3. "Our State Election". The Bristol Phoenix. April 2, 1870. Retrieved March 27, 2024– via NewspaperArchive.com.
4. "Democratic Nominations". Newport Daily News . March 25, 1869. Retrieved March 27, 2024– via Newspapers.com.