1893 Rhode Island gubernatorial election

1893 Rhode Island gubernatorial election

←  1892 April 5, 1893 1894  →

Dem Nominee Daniel Russell Brown David S. Baker Henry B. Metcalf Party Republican Democratic Prohibition Popular vote 21,830 22,015 3,265 Percentage 46.34% 46.73% 6.93%

County results Brown:      40–50%     50–60% Baker:      40–50%

Governor before election Daniel Russell Brown Republican Elected Governor Daniel Russell Brown Republican

The 1893 Rhode Island gubernatorial election was held on April 5, 1893. Incumbent Republican Daniel Russell Brown defeated Democratic nominee David S. Baker with 46.34% of the vote.

General election

Candidates

Major party candidates

• Daniel Russell Brown, Republican
• David S. Baker, Democratic

Other candidates

• Henry B. Metcalf, Prohibition

Results

1893 Rhode Island gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	Daniel Russell Brown (incumbent)	21,830	46.34%
	Democratic	David S. Baker	22,015	46.73%
	Prohibition	Henry B. Metcalf	3,265	6.93%
Majority			185
Turnout
	Republican hold		Swing

References

1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN   9780871879967 . Retrieved July 20, 2020.