1890 Rhode Island gubernatorial election

1890 Rhode Island gubernatorial election

←  1889 April 2, 1890 1891  →

Nominee John W. Davis Herbert W. Ladd Party Democratic Republican Popular vote 20,548 18,988 Percentage 48.76% 45.06%

County results Davis:      50–60% Ladd:      40–50%     50–60%

Governor before election Herbert W. Ladd Republican Elected Governor John W. Davis Democratic

The 1890 Rhode Island gubernatorial election was held on April 2, 1890. Democratic nominee John W. Davis defeated incumbent Republican Herbert W. Ladd with 48.76% of the vote.

General election

Candidates

Major party candidates

• John W. Davis, Democratic
• Herbert W. Ladd, Republican

Other candidates

• John H. Larry, Prohibition
• Arnold B. Chace, Union ^{[1] [2] [3]}

Results

1890 Rhode Island gubernatorial election ^[4]

Party		Candidate	Votes	%	±%
	Democratic	John W. Davis	20,548	48.76%
	Republican	Herbert W. Ladd (incumbent)	18,988	45.06%
	Prohibition	John H. Larry	1,820	4.32%
	Independent	Arnold B. Chace	752	1.78%
Majority			1,560
Turnout
	Democratic gain from Republican		Swing

References

1. "A Quaker for Governor". The sun. New York, N.Y. March 2, 1890. p. 18. Retrieved January 9, 2021.
2. "For the Suppression of Rum". Pittsburg dispatch. Pittsburg, Pa. February 26, 1890. p. 4. Retrieved January 9, 2021.
3. "Personal and Political". The herald. Milbank, S.D. March 4, 1890. p. 2. Retrieved January 9, 2021.
4. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN   9780871879967 . Retrieved July 27, 2020.