1867 Rhode Island gubernatorial election

1867 Rhode Island gubernatorial election

←  1866 3 April 1867 1868  →

Nominee Ambrose Burnside Lyman Pierce Party Republican Democratic Popular vote 7,372 3,178 Percentage 69.84% 30.11%

County results Burnside:      60–70%     70–80%

Governor before election Ambrose Burnside Republican Elected Governor Ambrose Burnside Republican

The 1867 Rhode Island gubernatorial election was held on 3 April 1867 in order to elect the governor of Rhode Island. Incumbent Republican governor Ambrose Burnside won re-election against Democratic nominee Lyman Pierce in a rematch of the previous election. ^[1]

General election

On election day, 3 April 1867, incumbent Republican governor Ambrose Burnside won re-election by a margin of 4,194 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of governor. Burnside was sworn in for his second term on 4 May 1867. ^[2]

Results

Rhode Island gubernatorial election, 1867

Party		Candidate	Votes	%
	Republican	Ambrose Burnside (incumbent)	7,372	69.84
	Democratic	Lyman Pierce	3,178	30.11
		Scattering	6	0.05
Total votes			10,556	100.00
	Republican hold

References

1. "Ambrose Burnside". National Governors Association . Retrieved April 7, 2024.
2. "RI Governor". ourcampaigns.com. July 26, 2005. Retrieved April 7, 2024.