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| Elections in Rhode Island |
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A presidential election was held in Rhode Island on November 6, 1844 as part of the 1844 United States presidential election. [1] Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
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Rhode Island voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Rhode Island by a margin of 19.97%.
With 59.55% of the popular vote, Rhode Island would prove to be Henry Clay's strongest state in the nation. [2]
