1879 Rhode Island gubernatorial election

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1879 Rhode Island gubernatorial election
Flag of Rhode Island (1877-1882).png
  1878 April 2, 1879 1880  
  CharlesVanZandt.jpg No image.svg
Nominee Charles C. Van Zandt Thomas W. Segar
Party Republican Democratic
Popular vote9,7175,506
Percentage62.09%35.18%

Governor before election

Charles C. Van Zandt
Republican

Elected Governor

Charles C. Van Zandt
Republican

The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.

Contents

General election

Candidates

Major party candidates

Other candidates

Results

1879 Rhode Island gubernatorial election [1]
PartyCandidateVotes%±%
Republican Charles C. Van Zandt (incumbent) 9,717 62.09%
Democratic Thomas W. Segar5,50635.18%
Greenback Samuel Hill3182.03%
Majority4,211
Turnout
Republican hold Swing

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References

  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN   9780871879967 . Retrieved November 1, 2020.