1792 United States presidential election in Rhode Island

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1792 United States presidential election in Rhode Island
Flag of Rhode Island.svg
November 2 – December 5, 1792 1796  
  George Washington Portrait (3x4 cropped).jpg George Clinton by Ezra Ames (3x4 cropped).jpg
Nominee George Washington George Clinton
Party Independent Democratic-Republican
Home state Virginia New York
Electoral vote44
Percentage100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Rhode Island took place as part of the 1792 United States presidential election. Voters chose four representatives, or electors to the Electoral College who voted for President and Vice President.

Contents

Rhode Island unanimously voted for the incumbent Independent President George Washington.

Results

1792 United States presidential election in Rhode Island [1]
PartyCandidateVotesPercentageElectoral votes
Independent George Washington (incumbent)4
Federalist John Adams 4
Totals8

See also

References

  1. "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 19, 2024.