1792 United States presidential election in Rhode Island

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1792 United States presidential election in Rhode Island
Flag of Rhode Island.svg
November 2 – December 5, 1792 1796  
  Gilbert Stuart Williamstown Portrait of George Washington.jpg
Nominee George Washington
Party Independent
Home state Virginia
Running mate George Clinton
Electoral vote4
Percentage100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Rhode Island took place as part of the 1792 United States presidential election. Voters chose four representatives, or electors to the Electoral College who voted for President and Vice President.

Contents

Rhode Island unanimously voted for the incumbent Independent President George Washington.

Results

1792 United States presidential election in Rhode Island [1]
PartyCandidateVotesPercentageElectoral votes
Independent George Washington (incumbent)4
Federalist John Adams 4
Totals8

See also

References

  1. "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 19, 2024.