1892 United States presidential election in Rhode Island

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1892 United States presidential election in Rhode Island
Flag of Rhode Island (1882-1897).svg
  1888 November 8, 1892 1896  
  Benjamin Harrison 1896.jpg StephenGroverCleveland.jpg
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Whitelaw Reid Adlai Stevenson I
Electoral vote40
Popular vote26,97524,336
Percentage50.71%45.75%

Rhode Island Presidential Election Results 1892.svg
County Results
Harrison
  40–50%
  50–60%

The 1892 United States presidential election in Rhode Island took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Rhode Island voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won the state by a narrow margin of 4.96%.

Results

1892 United States presidential election in Rhode Island [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Republican Benjamin Harrison of Indiana (incumbent) Whitelaw Reid of New York 26,97550.71%4100.00%
Democratic Grover Cleveland of New York Adlai Ewing Stevenson I of Illinois 24,33645.75%00.00%
Prohibition John Bidwell of California James Cranfill of Texas 1,6543.11%00.00%
Populist James Baird Weaver of Iowa James Gaven Field of Virginia 2280.43%00.00%
N/AOthersOthers30.01%00.00%
Total53,196100.00%4100.00%

See also

References

  1. "1892 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.