1796 United States presidential election in Rhode Island

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1796 United States presidential election in Rhode Island
Flag of Rhode Island.svg
  1792 November 4 – December 7, 1796 1800  
  Official Presidential portrait of John Adams (by John Trumbull, circa 1792).jpg
Nominee John Adams
Party Federalist
Home state Massachusetts
Running mate Thomas Pinckney
Electoral vote4
Percentage100.00%

President before election

George Washington
Independent

Elected President

John Adams
Federalist

The 1796 United States presidential election in Rhode Island took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.

Contents

During this election, Rhode Island cast its 4 electoral votes for John Adams. [1]

Results

1796 United States presidential election in Rhode Island [2] [3] :6–8
PartyCandidateVotesPercentageElectoral votes
Independent George Washington (incumbent)4
Federalist John Adams 4
Totals8

See also

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References

  1. "A New Nation Votes". elections.lib.tufts.edu. Retrieved 2024-08-29.
  2. "A New Nation Votes". elections.lib.tufts.edu. Retrieved 2024-08-29.
  3. Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson, North Carolina: McFarland. p. xii. ISBN   0-7864-1017-5.