1796 United States presidential election in Rhode Island

Main article: 1796 United States presidential election

1796 United States presidential election in Rhode Island

←  1792 November 4 – December 7, 1796 1800  →

Nominee John Adams Party Federalist Home state Massachusetts Running mate Thomas Pinckney Electoral vote 4 Percentage 100.00%

President before election George Washington Independent Elected President John Adams Federalist

The 1796 United States presidential election in Rhode Island took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election. Voters chose four representatives, or electors to the Electoral College who voted for president and vice president.

During this election, Rhode Island cast its four electoral votes for John Adams. ^[1]

Results

1796 United States presidential election in Rhode Island [2] [3] : 6–8
Party		Candidate	Votes	Percentage	Electoral votes
	Independent	George Washington (incumbent)	—	—	4
	Federalist	John Adams	—	—	4
Totals			—	—	8

See also

• United States presidential elections in Rhode Island

References

1. "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 29, 2024.
2. "A New Nation Votes". elections.lib.tufts.edu. Retrieved August 29, 2024.
3. Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson, North Carolina: McFarland. p. xii. ISBN   0-7864-1017-5.