1796 United States presidential election in Delaware

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1796 United States presidential election in Delaware
Flag of Delaware.svg
  1792 4 November – 7 December 1796 1800  
  Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg Thomas Jefferson by Rembrandt Peale, 1800.jpg
Nominee John Adams Thomas Jefferson
Party Federalist Democratic-Republican
Home state Massachusetts Virginia
Running mate Thomas Pinckney Aaron Burr
Electoral vote30
Percentage100.00%0.00%

The 1796 United States presidential election in Delaware took place between 4 November and 7 December 1796, as part of the 1796 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Delaware cast three electoral votes for the Federalist candidate and incumbent vice president John Adams over the Democratic-Republican candidate Thomas Jefferson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for vice president were cast for Adams' running mate Thomas Pinckney from South Carolina. [1]

Results

1796 United States presidential election in Delaware [2]
PartyCandidateVotesPercentageElectoral votes
Federalist John Adams 100.00%3
Democratic-Republican Thomas Jefferson 0.00%0
Totals3

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References

  1. "1796 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
  2. "1796 Presidential Election". 270towin.com. Retrieved July 9, 2023.