1819 Delaware gubernatorial election

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1819 Delaware gubernatorial election
Flag of Delaware.svg
  1816 October 5, 1819 1820 (special)  
  No image.svg No image.svg
Nominee Henry Molleston Manaen Bull
Party Federalist Democratic-Republican
Popular vote3,8233,185
Percentage54.55%45.45%

1819 Delaware gubernatorial election results map by county.svg
Molleston:     50–60%     60–70%
Bull:     60–70%

Governor before election

John Clark
Federalist

Elected Governor

Henry Molleston
Federalist

The 1819 Delaware gubernatorial election was held on October 5, 1819. Incumbent Federalist Governor John Clark was unable to seek re-election due to term limits. State Senator Henry Molleston ran as Clark's successor, winning the Federalist nomination. He faced Manaen Bull, Clark's 1816 opponent, and the Democratic-Republican nominee. Molleston won by a fairly wide margin, but died on November 11, 1819, prior to assuming office. State Senate President Jacob Stout became Governor and a special election was held in 1820. [1]

Contents

General election

Results

1819 Delaware gubernatorial election [2]
PartyCandidateVotes%±%
Federalist Henry Molleston 3,823 54.55% +1.29%
Democratic-Republican Manaen Bull3,18545.45%−1.29%
Majority6389.10%+2.58%
Turnout 7,008100.00%
Federalist hold

References

  1. Conrad, Henry C. (1908). History of the State of Delaware: From the Earliest Settlements to the Year 1907. Vol. 1. Lancaster, Pa.: Wickersham Company, Printers and Binders. p. 176.
  2. "Delaware 1819 Governor". A New Nation Votes: American Election Returns 1787-1825. Tufts University. Retrieved June 17, 2021.

Bibliography