1806 United States House of Representatives election in Delaware

1806 United States House of Representatives election in Delaware

←  1805 (special) October 7, 1806 (1806-10-07) 1807 (special)  →

Candidate James M. Broom Thomas Fitzgerald Party Federalist Democratic-Republican Popular vote 2,353 830 Percentage 60.52% 21.35%   Candidate Joseph Haslet Thomas Montgomery Party Democratic-Republican Democratic-Republican Popular vote 382 323 Percentage 9.83% 8.31%

U.S. representative before election James M. Broom Federalist Elected U.S. representative James M. Broom Federalist

The 1806 United States House of Representatives election in Delaware was held on October 7, 1806, to elect the U.S. representative from Delaware's at-large congressional district. Incumbent Federalist James M. Broom faced re-election to a full term after winning the previous year's special election. He was challenged by three Democratic-Republicans.

Broom was re-elected with over 60% of the vote, with neither opponent coming close to unseating him.

Results

1806 United States House of Representatives election in Delaware ^[1]

Party		Candidate	Votes	%
	Federalist	James M. Broom (incumbent)	2,353	60.52
	Democratic-Republican	Thomas Fitzgerald	830	21.35
	Democratic-Republican	Joseph Haslet	382	9.83
	Democratic-Republican	Thomas Montgomery	323	8.31
Majority			1,523	39.17
Total votes			3,888	100.00
	Federalist hold

Results by county

County	Broom#	Broom%	Fitzgerald#	Fitzgerald%	Haslet#	Haslet%	Montgomery#	Montgomery%	Total
Kent	709	95.94%					30	4.06%	739
New Castle	928	43.36%	830	38.79%	382	17.85%			2,140
Sussex	719	71.05%					293	28.95%	1,012

See also

• 1807 Delaware's at-large congressional district special election
• 1806 and 1807 United States House of Representatives elections
• List of United States representatives from Delaware

References

1. "Our Campaigns - DE District At Large Race - Oct 07, 1806". Our Campaigns. January 10, 2006.