1904 United States presidential election in Delaware

Main article: 1904 United States presidential election

1904 United States presidential election in Delaware

←  1900 November 8, 1904 1908  →

Nominee Theodore Roosevelt Alton B. Parker Party Republican Democratic Home state New York New York Running mate Charles W. Fairbanks Henry G. Davis Electoral vote 3 0 Popular vote 23,705 19,347 Percentage 54.05% 44.11%

County Results Roosevelt   50–60%

President before election Theodore Roosevelt Republican Elected President Theodore Roosevelt Republican

The 1904 United States presidential election in Delaware took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. They defeated the Democratic nominees, former Chief Judge of New York Court of Appeals Alton B. Parker and his running mate Henry G. Davis. Roosevelt won the state by a margin of 9.94%.

Results

1904 United States presidential election in Delaware [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Theodore Roosevelt (inc.)	23,705	54.05%	3
	Democratic	Alton B. Parker	19,347	44.11%	0
	Prohibition	Silas C. Swallow	607	1.38%	0
	Social Democratic	Eugene V. Debs	146	0.33%	0
	Populist	Thomas E. Watson	51	0.12%	0
Totals			43,856	100.00%	3
Voter turnout					—

See also

• United States presidential elections in Delaware

References

1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware