1816 United States presidential election in Delaware

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1816 United States presidential election in Delaware
Flag of Delaware.svg
  1812 1 November – 4 December 1816 1820  
  Gilbert Stuart - Portrait of Rufus King (1819-1820) - Google Art Project.jpg John Vanderlyn - James Monroe - Google Art Project.jpg
Nominee Rufus King James Monroe
Party Federalist Democratic-Republican
Home state New York Virginia
Running mate John E. Howard Daniel D. Tompkins
Electoral vote30

The 1816 United States presidential election in Delaware took place between 1 November and 4 December 1816, as part of the 1816 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Delaware cast three electoral votes for the Federalist candidate Rufus King over the Democratic-Republican candidate James Monroe. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. However one of the four electors did not end up casting their vote. The three electoral votes for Vice president were also not cast for King's running mate John E. Howard, but for Federalist Robert Goodloe Harper from Maryland. [1]

Results

1816 United States presidential election in Delaware [2]
PartyCandidateVotesPercentageElectoral votes
Federalist Rufus King 3
Democratic-Republican James Monroe 0
NoneNot Cast1
Totals4

See also

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References

  1. "1816 Presidential General Election Results". U.S. Election Atlas. Retrieved July 8, 2023.
  2. "1816 Presidential Election". 270towin.com. Retrieved July 8, 2023.