1856 United States presidential election in Delaware

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1856 United States presidential election in Delaware
Flag of Delaware.svg
  1852 November 4, 1856 1860  
  James Buchanan.jpg Fillmore.jpg
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew Jackson Donelson
Electoral vote30
Popular vote8,0046,275
Percentage54.83%42.99%

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Delaware took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Delaware voted for the Democratic candidate, James Buchanan, over the Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore.

Buchanan won the state by a margin of 11.84%.

Results

1856 United States presidential election in Delaware [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 8,00454.83%3100.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 6,27542.99%00.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 3102.12%00.00%
N/AOthersOthers90.06%00.00%
Total14,598100.00%3100.00%

See also

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References

  1. "1856 Presidential General Election Results - Delaware".