1856 United States presidential election in Georgia

Main article: 1856 United States presidential election

1856 United States presidential election in Georgia

←  1852 November 4, 1856 1860  →

Nominee James Buchanan Millard Fillmore Party Democratic Know Nothing Home state Pennsylvania New York Running mate John C. Breckinridge Andrew J. Donelson Electoral vote 10 0 Popular vote 56,581 42,439 Percentage 57.14% 42.86%

County Results Buchanan   50–60%   60–70%   70–80%   80–90%   90–100% Fillmore   50–60%   60–70%   70–80%   80–90% Tie

President before election Franklin Pierce Democratic Elected President James Buchanan Democratic

The 1856 United States presidential election in Georgia took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

Georgia voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Georgia by a margin of 14.28%.

Republican Party candidate John C. Frémont was not on the ballot in the state, despite being born in Savannah.

Results

1856 United States presidential election in Georgia [1] [2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	James Buchanan of Pennsylvania	John C. Breckinridge of Kentucky	56,581	57.14%	10	100.00%
	Know Nothing	Millard Fillmore of New York	Andrew Jackson Donelson of Tennessee	42,439	42.86%	0	0.00%
Total				99,020	100.00%	10	100.00%

References

1. "1856 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved December 3, 2017.
2. "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.