1800 United States presidential election in Georgia

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1800 United States presidential election in Georgia
Flag of Georgia (U.S. state).svg
  1796 31 October – 3 December 1800 1804  
  Thomas Jefferson by Rembrandt Peale, 1800.jpg Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg
Nominee Thomas Jefferson John Adams
Party Democratic-Republican Federalist
Home state Virginia Massachusetts
Running mate Aaron Burr Charles C. Pinckney
Electoral vote40
Percentage100.00%-

The 1800 United States presidential election in Georgia took place between 31 October and 3 December 1800, as part of the 1800 United States presidential election. The state legislature chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Georgia cast four electoral votes for the Democratic-Republican candidate and incumbent Vice President Thomas Jefferson over the Federalist candidate and incumbent President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. These electors were elected by the Georgia General Assembly, the state legislature, rather than by popular vote. [1]

Results

1800 United States presidential election in Georgia [2]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Thomas Jefferson 100.00%4
Federalist John Adams (incumbent)0
Totals100.00%4

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References

  1. "1800 Presidential General Election Results". U.S. Election Atlas. Retrieved July 10, 2023.
  2. "1800 Presidential Election". 270towin.com. Retrieved July 10, 2023.