1844 United States presidential election in Georgia

Main article: 1844 United States presidential election

1844 United States presidential election in Georgia

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Nominee James K. Polk Henry Clay Party Democratic Whig Home state Tennessee Kentucky Running mate George M. Dallas Theodore Frelinghuysen Electoral vote 10 0 Popular vote 44,147 42,100 Percentage 51.19% 48.81%

County Results Polk   50–60%   60–70%   70–80%   80–90%   90–100% Clay   50–60%   60–70%   70–80%   80–90%   90–100%

President before election John Tyler Independent Elected President James K. Polk Democratic

A presidential election was held in Georgia on November 4, 1844 as part of the 1844 United States presidential election. ^[1] Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Georgia by a margin of 2.38%.

Results

United States presidential election in Georgia, 1844 [2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	James K. Polk of Tennessee	George M. Dallas of Pennsylvania	44,147	51.19%	10	100.00%
	Whig	Henry Clay of Kentucky	Theodore Frelinghuysen of New York	42,100	48.81%	0	0.00%
Total				86,247	100.00%	10	100.00%

References

1. Presidential Elections, 1844. [Boston]. 1844.
2. "1844 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved December 23, 2013.