1844 United States presidential election in New Jersey

Main article: 1844 United States presidential election

1844 United States presidential election in New Jersey

←  1840 November 5, 1844 1848  →

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Nominee Henry Clay James K. Polk Party Whig Democratic Home state Kentucky Tennessee Running mate Theodore Frelinghuysen George M. Dallas Electoral vote 7 0 Popular vote 38,318 37,495 Percentage 50.46% 49.37%

County Results Clay   50–60%   60–70%   70–80% Polk   50–60%   60–70%   70–80%

President before election John Tyler Independent Elected President James K. Polk Democratic

A presidential election was held in New Jersey on November 5, 1844 as part of the 1844 United States presidential election. ^[1] Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won New Jersey by a margin of 1.09 percent; however, Polk would be the last Democrat to carry Cape May County until Woodrow Wilson in 1912. ^[2] This is the last time a Democrat won without carrying Hudson County.

Results

1844 United States presidential election in New Jersey [3]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	Henry Clay of Kentucky	Theodore Frelinghuysen of New York	38,318	50.46%	7	100.00%
	Democratic	James K. Polk of Tennessee	George M. Dallas of Pennsylvania	37,495	49.37%	0	0.00%
	Liberty	James G. Birney of Michigan	Thomas Morris of Ohio	131	0.17%	0	0.00%
Total				75,944	100.00%	7	100.00%

See also

• United States presidential elections in New Jersey

References

1. Presidential Elections, 1844. [Boston]. 1844.
2. Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 258-259 ISBN   0786422173
3. "1844 Presidential General Election Results – New Jersey". U.S. Election Atlas. Retrieved December 23, 2013.