1808 United States presidential election in New Jersey

Main article: 1808 United States presidential election

1808 United States presidential election in New Jersey

←  1804 November 4 – December 7, 1808 1812  →

Nominee James Madison Charles Cotesworth Pinckney Party Democratic-Republican Federalist Home state Virginia South Carolina Running mate George Clinton Rufus King Electoral vote 8 0 Popular vote 18,670 14,687 Percentage 55.97% 44.03%

County Results Madison   50–60%   60–70%   80–90% Pinckney   50–60%   60–70%   70–80%

President before election Thomas Jefferson Democratic-Republican Elected President James Madison Democratic-Republican

The 1808 United States presidential election in New Jersey took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. The state chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, New Jersey cast its eight electoral votes to Democratic Republican candidate and Secretary of State James Madison. ^[1]

See also

• United States presidential elections in New Jersey

References

1. Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. p. 15. ISBN   9780786410170.