1808 United States presidential election in Ohio

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1808 United States presidential election in Ohio
Flag of Ohio.svg
  1804
1812  
  James Madison.jpg CharlesCPinckney (cropped).png John Vanderlyn - James Monroe - Google Art Project.jpg
Nominee James Madison Charles C. Pinckney James Monroe
Party Democratic-Republican Federalist Tertium quids
Home state Virginia South Carolina Virginia
Running mate George Clinton Rufus King none
Electoral vote300
Popular vote3,6451,1741,174
Percentage60.82%19.59%19.59%

President before election

Thomas Jefferson
Democratic-Republican

Elected President

James Madison
Democratic-Republican

The 1808 United States presidential election in Ohio took place as part of the 1808 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president.

James Madison, the nominee of the governing Democratic-Republican Party, defeated Federalist Party challenger Charles C. Pinckney and fellow Democratic-Republican James Monroe, who ran as the candidate of the Tertium quids, by 2,471 votes (41.23%). Monroe would later succeed Madison as the fifth president of the United States in 1817. [1]

Results

1808 United States presidential election in Ohio [2]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican James Madison 3,64560.82%3
Federalist Charles Cotesworth Pinckney 1,17419.590
Tertium quids James Monroe 1,17419.590
Totals5,993100.0%3

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References

  1. Lampi, Philip. "Ohio 1808 Electoral College". A New Nation Votes. Tufts University. Retrieved July 11, 2021.
  2. Lampi, Philip. "Ohio 1808 Electoral College". A New Nation Votes. Tufts University. Retrieved July 11, 2021.