1808 United States presidential election in Ohio

Main article: 1808 United States presidential election

1808 United States presidential election in Ohio

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Nominee James Madison Charles Cotesworth Pinckney James Monroe Party Democratic-Republican Federalist Tertium quids Home state Virginia South Carolina Virginia Running mate George Clinton Rufus King none Electoral vote 3 0 0 Popular vote 3,645 1,174 1,174 Percentage 60.82% 19.59% 19.59%

President before election Thomas Jefferson Democratic-Republican Elected President James Madison Democratic-Republican

The 1808 United States presidential election in Ohio took place as part of the 1808 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president.

James Madison, the nominee of the governing Democratic-Republican Party, defeated Federalist Party challenger Charles Cotesworth Pinckney and fellow Democratic-Republican James Monroe, who ran as the candidate of the Tertium quids, by 2,471 votes (41.23%). Monroe would later succeed Madison as the fifth president of the United States in 1817. ^[1]

Results

1808 United States presidential election in Ohio [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	James Madison	3,645	60.82%	3
	Federalist	Charles Cotesworth Pinckney	1,174	19.59	0
	Tertium quids	James Monroe	1,174	19.59	0
Totals			5,993	100.0%	3

See also

• United States presidential elections in Ohio

References

1. Lampi, Philip. "Ohio 1808 Electoral College". A New Nation Votes. Tufts University. Retrieved July 11, 2021.
2. Lampi, Philip. "Ohio 1808 Electoral College". A New Nation Votes. Tufts University. Retrieved July 11, 2021.