1828 United States presidential election in Ohio

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1828 United States presidential election in Ohio
Flag of Ohio.svg
  1824 October 31 – December 2, 1828 1832  
  Andrew Jackson.jpg John Quincy Adams 1858 crop.jpg
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote160
Popular vote67,59563,394
Percentage51.60%48.40%

Ohio Presidential Election Results 1828.svg
County Results

President before election

John Quincy Adams
Democratic-Republican

Elected President

Andrew Jackson
Democratic

The 1828 United States presidential election in Ohio took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Ohio voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Ohio by a narrow margin of 3.2%. This was the first election of the Second Party System, and as such the first election in which Ohio voted for a candidate of a party other than the Democratic-Republicans.

Results

1828 United States presidential election in Ohio [1]
PartyCandidateVotesPercentageElectoral votes
Democratic Andrew Jackson 67,59751.60%16
National Republican John Quincy Adams (incumbent)63,39648.40%0
Totals130,993100.0%16

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References

  1. "1828 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved February 28, 2013.