1828 United States presidential election in Ohio

Main article: 1828 United States presidential election

1828 United States presidential election in Ohio

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Nominee Andrew Jackson John Quincy Adams Party Democratic National Republican Home state Tennessee Massachusetts Running mate John C. Calhoun Richard Rush Electoral vote 16 0 Popular vote 67,595 63,394 Percentage 51.60% 48.40%

County Results Jackson   50–60%   60–70%   70–80% Adams   50–60%   60–70%   70–80%   80–90%   90–100%

President before election John Quincy Adams Democratic-Republican Elected President Andrew Jackson Democratic

The 1828 United States presidential election in Ohio took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Ohio by a narrow margin of 3.2%. This was the first election of the Second Party System, and as such the first election in which Ohio voted for a candidate of a party other than the Democratic-Republicans.

Results

1828 United States presidential election in Ohio [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Andrew Jackson	67,597	51.60%	16
	National Republican	John Quincy Adams (incumbent)	63,396	48.40%	0
Totals			130,993	100.0%	16

See also

• United States presidential elections in Ohio

References

1. "1828 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved February 28, 2013.