1828 United States presidential election in Pennsylvania

Main article: 1828 United States presidential election

1828 United States presidential election in Pennsylvania

←  1824 October 31 – December 2, 1828 1832  →

Nominee Andrew Jackson John Quincy Adams Party Democratic National Republican Home state Tennessee Massachusetts Running mate John C. Calhoun Richard Rush Electoral vote 28 0 Popular vote 101,652 50,848 Percentage 66.66% 33.34%

County Results Jackson   50–60%   60–70%   70–80%   80–90% Adams   50–60%

President before election John Quincy Adams Democratic-Republican Elected President Andrew Jackson Democratic

The 1828 United States presidential election in Pennsylvania took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 28 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Pennsylvania by a margin of 33.32%.

To date, this is still the best Democratic Party performance in Pennsylvania in any federal election.

Results

1828 United States presidential election in Pennsylvania [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Andrew Jackson	101,652	66.66%	28
	National Republican	John Quincy Adams (incumbent)	50,848	33.34%	0
Totals			152,500	100.0%	28

References

1. "1828 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.