1828 United States presidential election in Tennessee

Main article: 1828 United States presidential election

1828 United States presidential election in Tennessee

←  1824 October 31 – December 2, 1828 1832  →

Nominee Andrew Jackson John Quincy Adams Party Democratic National Republican Home state Tennessee Massachusetts Running mate John C. Calhoun Richard Rush Electoral vote 11 0 Popular vote 44,293 2,240 Percentage 95.19% 4.81%

County results Jackson   80–90%   90–100% Unknown/No vote

President before election John Quincy Adams National Republican Elected President Andrew Jackson Democratic

The 1828 United States presidential election in Tennessee took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

Tennessee voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Tennessee, his home state, by a wide margin of 90.38%. This is the last time any party swept every Tennessee county and the best ever performance for Democrat in a Presidential election in Tennessee.

Results

1828 United States presidential election in Tennessee [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Andrew Jackson	44,293	95.19%	11
	National Republican	John Quincy Adams (incumbent)	2,240	4.81%	0
Totals			46,533	100.0%	11

See also

• United States presidential elections in Tennessee

References

1. "1828 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved February 28, 2013.