1828 United States presidential election in New Jersey

Main article: 1828 United States presidential election

1828 United States presidential election in New Jersey

←  1824 October 31 – December 2, 1828 1832  →

Nominee John Quincy Adams Andrew Jackson Party National Republican Democratic Home state Massachusetts Tennessee Running mate Richard Rush John C. Calhoun Electoral vote 8 0 Popular vote 23,753 21,809 Percentage 52.12% 47.86%

County Results Adams   50–60%   60–70%   70–80% Jackson   50–60%   60–70%   70–80%

President before election John Quincy Adams National Republican Elected President Andrew Jackson Democratic

The 1828 United States presidential election in New Jersey took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won New Jersey by a narrow margin of 4.26%.

Results

1828 United States presidential election in New Jersey [1]
Party		Candidate	Votes	Percentage	Electoral votes
	National Republican	John Quincy Adams (incumbent)	23,753	52.12%	8
	Democratic	Andrew Jackson	21,809	47.86%	0
	N/A	Other	8	0.02%	0
Totals			45,570	100.0%	8

See also

• United States presidential elections in New Jersey

References

1. "1828 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved February 28, 2013.