1824 United States presidential election in New Jersey

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1824 United States presidential election in New Jersey
Flag of New Jersey.svg
  1820 October 26 – December 2, 1824 1828  
  Andrew Jackson.jpg John Quincy Adams 1858 crop.jpg WilliamHCrawford.jpg
Nominee Andrew Jackson John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican Democratic-Republican
Home state Tennessee Massachusetts Georgia
Running mate John C. Calhoun John C. Calhoun Nathaniel Macon
Electoral vote800
Popular vote10,3328,3091,196
Percentage52.08%41.89%6.03%

New Jersey Presidential Election Results 1824.svg
County Results

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in New Jersey took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. New Jersey voted for Andrew Jackson over John Quincy Adams, William H. Crawford, and Henry Clay. Jackson won New Jersey by over half of the vote.

Results

1824 United States presidential election in New Jersey [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Andrew Jackson 10,33252.08%8
Democratic-Republican John Quincy Adams 8,30941.89%0
Democratic-Republican William H. Crawford 1,1966.03%0
Totals19,837100.0%8

See also

References

  1. "1824 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved February 27, 2013.