1824 United States presidential election in Alabama

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1824 United States presidential election in Alabama
Flag of Alabama.svg
  1820 October 26 – December 2, 1824 1828  
  Andrew Jackson.jpg John Quincy Adams 1858 crop.jpg WilliamHCrawford.jpg
Nominee Andrew Jackson John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican Democratic-Republican
Home state Tennessee Massachusetts Georgia
Running mate John C. Calhoun John C. Calhoun Nathaniel Macon
Electoral vote500
Popular vote9,4292,4221,656
Percentage69.32%17.80%12.17%

Alabama Presidential Election Results 1824.svg
County Results

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in Alabama took place between October 26 and December 2, 1824, as part of the 1824 presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.

Contents

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Alabama voted for Andrew Jackson over John Quincy Adams, William H. Crawford and Henry Clay. Jackson won Alabama by a margin of 51.52%. This was the first time since achieving statehood in 1819 that Alabama backed the losing candidate in a presidential election.

Results

1824 United States presidential election in Alabama [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Andrew Jackson 9,42969.32%5
Democratic-Republican John Quincy Adams 2,42217.80%0
Democratic-Republican William H. Crawford 1,65612.17%0
Democratic-Republican Henry Clay 960.71%0
Totals13,423100.00%5

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References

  1. "1824 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved February 27, 2013.