1824 United States presidential election in Mississippi

Main article: 1824 United States presidential election

1824 United States presidential election in Mississippi

←  1820 October 26 – December 2, 1824 1828  →

Nominee Andrew Jackson John Quincy Adams Party Democratic-Republican Democratic-Republican Home state Tennessee Massachusetts Running mate John C. Calhoun John C. Calhoun Electoral vote 3 0 Popular vote 3,121 1,654 Percentage 63.77% 33.80%

Jackson   40–50%   50–60%   70–80%   80–90%   90–100% Unknown/No Vote

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

The 1824 United States presidential election in Mississippi took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Mississippi voted for Andrew Jackson over John Quincy Adams, William H. Crawford and Henry Clay. Jackson won Mississippi by a margin of 29.97%.

Results

1824 United States presidential election in Mississippi [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Andrew Jackson	3,121	63.77%	3
	Democratic-Republican	John Quincy Adams	1,654	33.80%	0
	Democratic-Republican	William H. Crawford	119	2.43%	0
Totals			4,894	100.0%	3

See also

• United States presidential elections in Mississippi

References

1. "1824 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved February 27, 2013.