1824 United States presidential election in Mississippi

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1824 United States presidential election in Mississippi
US flag 24 stars.svg
 1820October 26 – December 2, 1824 1828  
  Andrew Jackson.jpg John Quincy Adams 1858 crop.jpg
Nominee Andrew Jackson John Quincy Adams
Party Democratic-Republican Democratic-Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun John C. Calhoun
Electoral vote30
Popular vote3,1211,654
Percentage63.77%33.80%

1824 Presidential Election in Mississippi.svg

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in Mississippi took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Mississippi voted for Andrew Jackson over John Quincy Adams, William H. Crawford and Henry Clay. Jackson won Mississippi by a margin of 29.97%.

Results

United States presidential election in Mississippi, 1824 [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Andrew Jackson 3,12163.77%3
Democratic-Republican John Quincy Adams 1,65433.80%0
Democratic-Republican William H. Crawford 1192.43%0
Totals4,894100.0%3

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References

  1. "1824 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved 27 February 2013.