1864 United States presidential election in New Jersey

Main article: 1864 United States presidential election

1864 United States presidential election in New Jersey

←  1860 November 8, 1864 1868  →

Nominee George B. McClellan Abraham Lincoln Party Democratic National Union Home state New Jersey Illinois Running mate George H. Pendleton Andrew Johnson Electoral vote 7 0 Popular vote 68,024 60,723 Percentage 52.84% 47.16%

County Results McClellan   50–60%   60–70% Lincoln   50–60%   60–70%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln National Union

The 1864 United States presidential election in New Jersey took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey voted for the Democratic candidate, George B. McClellan, over the National Union candidate, incumbent president Abraham Lincoln. McClellan won his home state by a narrow margin of 5.68%. New Jersey was one of the three states McClellan won, with the other two being Delaware and Kentucky.

With 52.84% of the popular vote, New Jersey would prove to be McClellan's second strongest after Kentucky. ^[1]

Results

1864 United States presidential election in New Jersey [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	George B. McClellan	68,024	52.84%	7
	National Union	Abraham Lincoln (incumbent)	60,723	47.16%	0
Totals			128,747	100.0%	7

See also

• United States presidential elections in New Jersey

References

1. "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
2. "1864 Presidential General Election Results - New Jersey".