1864 United States presidential election in Michigan

Main article: 1864 United States presidential election

1864 United States presidential election in Michigan

←  1860 November 8, 1864 1868  →

Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois New Jersey Running mate Andrew Johnson George H. Pendleton Electoral vote 8 0 Popular vote 79,149 68,513 Percentage 53.60% 46.40%

County Results Lincoln   50–60%   60–70%   70–80%   80–90% McClellan   50–60%   60–70%   70–80%   80–90%   90–100%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln National Union

The 1864 United States presidential election in Michigan took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose eight ^[1] representatives, or electors, to the Electoral College, who voted for president and vice president. ^[2]

Michigan was won by National Union candidate, incumbent Republican president Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic challenger George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a margin of 7.2%. ^[2]

As of the 2024 presidential election ^[update] , this is the last time Ottawa County voted for a Democratic presidential candidate. ^[3]

Results

1864 United States presidential election in Michigan ^[2]

Party		Candidate	Votes	%
	National Union	Abraham Lincoln (incumbent)	79,149	53.60%
	Democratic	George B. McClellan	68,513	46.40%
Total votes			147,662	100%

See also

• United States presidential elections in Michigan

References

1. "1864 Election for the Twentieth Term (1865-1869)" . Retrieved November 28, 2018.
2. "1864 Presidential General Election Results - Michigan".
3. Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 222-227 ISBN   0786422173