1840 United States presidential election in Michigan

Main article: 1840 United States presidential election

1840 United States presidential election in Michigan

←  1836 October 30 - December 2, 1840 1844  →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 3 0 Popular vote 22,933 21,096 Percentage 51.71% 47.57%

County Results Harrison   40-50%   50-60%   60-70% Van Buren   40-50%   50-60%   60-70%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

The 1840 United States presidential election in Michigan took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Michigan voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Michigan by a narrow margin of 4.14%. This was the only time Michigan voted for a Whig Party candidate.

Results

1840 United States presidential election in Michigan ^[1]

Party		Candidate	Votes	%
	Whig	William Henry Harrison	22,933	51.71%
	Democratic	Martin Van Buren	21,096	47.57%
	Liberty	James G. Birney	321	0.72%
Total votes			44,350	100%

See also

• United States presidential elections in Michigan

References

1. "1840 Presidential General Election Results - Michigan". U.S. Election Atlas. Retrieved December 23, 2013.