1840 United States presidential election in Illinois

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1840 United States presidential election in Illinois
Flag of Illinois.svg
  1836 October 30 – December 2, 1840 1844  
  Martin Van Buren circa 1837 crop.jpg William Henry Harrison crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Mentor Johnson John Tyler
Electoral vote50
Popular vote47,44145,574
Percentage50.92%48.91%

Illinois Presidential Election Results 1840.png
County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in Illinois took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Illinois voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Illinois by a margin of 2.01%.

Results

1840 United States presidential election in Illinois [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 47,44150.92%5100.00%
Whig William Henry Harrison of Ohio John Tyler of Virginia 45,57448.91%00.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 1600.17%00.00%
Total93,175100.00%5100.00%

See also

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References

  1. "1840 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved December 23, 2013.