1840 United States presidential election in Illinois

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1840 United States presidential election in Illinois

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Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Mentor Johnson John Tyler Electoral vote 5 0 Popular vote 47,441 45,574 Percentage 50.92% 48.91%

County Results Van Buren   50-60%   60-70%   70-80%   80–90% Harrison   50-60%   60-70%   70-80%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

A presidential election was held in Illinois on November 2, 1840 as part of the 1840 United States presidential election. ^[1] Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Illinois voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Illinois by a margin of 2.01%.

Results

1840 United States presidential election in Illinois [2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	47,441	50.92%	5	100.00%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	45,574	48.91%	0	0.00%
	Liberty	James G. Birney of New York	Thomas Earle of Pennsylvania	160	0.17%	0	0.00%
Total				93,175	100.00%	5	100.00%

See also

• United States presidential elections in Illinois

References

1. Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
2. "1840 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved December 23, 2013.